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Michael

Spoilers · 01/24/2015 4:56 PM

: \tan{\frac{\alpha}{2}}\tan{\frac{\beta}{2}}+\tan{\frac{\beta}{2}}\tan{\frac{\gamma}{2}}+\tan{\frac{\gamma}{2}}\tan{\frac{\alpha}{2}}=1,[6] \sin^2{\frac{\alpha}{2}}+\sin^2{\frac{\beta}{2}}+\sin^2{\frac{\gamma}{2}}+2\sin{\frac{\alpha}{2}}\sin{\frac{\beta}{2}}\sin{\frac{\gamma}{2}}=1,[6] \sin(2\alpha) + \sin(2\beta) + \sin(2\gamma) = 4\sin(\alpha)\sin(\beta)\sin(\gamma), \tan(\a

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